HMD 436 Name___________________
Final Exam
May 13, 2002 6:00-800 PM
(1/6)^2 = 1/36
Ways to roll a 6: 1+5, 2+4, 3+3, 4+2, 5+1 = 5. So the probability is 5/6^2 = 5/36
13*combin(4,2)/combin(52,2) = 13*6/1326 = 1/17 = 0.0588
(4*4)*(16*4)/combin(52*4,2) = 16*64/21528 = 0.0476
7! = 5040
Combin(12,4) = 495
Combin(10,2)*combin(15,4)/combin(25,6) = 45*1365/177100 = 0.3468
Ways to roll a 5: 1+4, 2+3, 3+2, 4+1 = 4.
Probability of a 5: 4/36
Expected number of rolls is 1/(4/36) = 36/4 = 9
Combin(52,7) = 133784560
13*12*combin(4,3)*combin(4,2)/combin(52,5) = 13*12*4*6/2598960 = 3744/2598960 = 0.0014406.
Probability of 7 = 6/36
Probability of 9 = 4/36
Probability of 9 before 7 = (4/36)/((6/36)+(4/36)) = (4/36)/(10/36) = 4/10 = 2/5
12. What is the probability of being dealt (before the draw) a sequential royal flush in either direction in normal 52-card deck video poker? (4 points)
2*4/permut(52,5) = 8/311875200=2.5651*10^-8
For questions 13,14 consider a modified deck with 16 ranks and 6 suits. The ace can be high or low.
6*(combin(16,5)-13) = 6*(4368-13) = 26130.
Combin(16,2)*14*combin(6,2)^2*6 = 120*14*15^2*6 = 2268000
Problems 15,16 are all based on blackjack side bets.
2*combin(2*8,4)/combin(8*52,4) = 2*combin(16,4)/combin(416,4) = 2*1820/1229930520 = 2.9595*10^-6
permut(4,2)*6^2*(48*6)/permut(52*6,3) = 12*6^2*288/30079920 = 0.0041362
Total numbers along frame = 16.
Total numbers not on frame = 75-16 = 59
Total calls other than frame numbers = 50-16 = 34
Combin(59,34)/combin(75,50) = (3.0284*10^16)/(5.2589*10^19) = 0.00057587
1-(1-0.00057587)^500 =
Chicago (-140) Vs. Houston (+120).
Assuming a fair set of lines would have been -130 and +130 what is the probability that Atlanta will win? (4 points)
P*100 + (1-p)*-130 = 0
230p = 130
p=130/230 = 13/23 = 0.5652
((13/23)*100 + (10/23)*-140)/140 = (-100/23)/140 = -0.0311
Probability of win = .7^5 = 0.1681
Probability of loss = 1-.7^5 = 0.8319
EV = .1681*(7/2) + .8319*-1 = -0.2437
Original pool = $100,000
After track cut = $100,000*82% = $82,000
After winning bets = $82,000-$6000-$9000 = $67,000
Each place bet pool = $67,000/2 = $33,500
Ratio of winnings to original bet = $33,500/$6000 = 5.5833
Value of $2 ticket = $2+$2*(5.5833) = $2 + $11.17 = $13.17
Value of $2 ticket after rounding = $13.10
Value of $20 ticket = $22.30 * ($20/$2) = $131.00
|
Event |
Probability |
Pays |
E(x) |
E(x^2) |
|
Win |
0.105263 |
8 |
0.842105 |
6.736842 |
|
Loss |
0.894737 |
-1 |
-0.894737 |
0.894737 |
|
Total |
1.000000 |
-0.052632 |
7.631579 |
Variance per spin = 7.681579 – (-0.052632)^2 =
7.628809Standard deviation = 7.628809^0.5 = 2.762030
Total standard deviation = 2.762030*500^0.5 = 61.760865
Expected win = 500*(-0.052632) = -26.315789
Z = (100-0.5-(-26.315789))/ 61.760865 = 2.037144
Pr (z>=2.037144) = 1-pr(z<=2.037144) = 0.020818
Key chain 30%
Deck of cards 20%
Buffet coupon 15%
Show ticket 10%
Dice clock 10%
T-shirt 10%
Jacket 4%
$1000 1%
Following is the wheel’s actual and expected results over 10,000 spins. You may use the chi-squared column for your own work. What is the chi-squared statistic and what is the probability that a fair test would be this skewed or more? (8 points)
|
Prize |
Expected |
Actual |
Chi-squared |
|
Key chain |
3000 |
2970 |
0.3 |
|
Deck of cards |
2000 |
1920 |
3.2 |
|
Buffet |
1500 |
1440 |
2.4 |
|
Show ticket |
1000 |
1020 |
0.4 |
|
Dice clock |
1000 |
1040 |
1.6 |
|
T-shirt |
1000 |
1060 |
3.6 |
|
Jacket |
400 |
430 |
2.25 |
|
$1,000 |
100 |
120 |
4 |
|
Total |
10000 |
10000 |
17.75 |
Probability that chi-squared statistic with 7 degrees of freedom is greater than 17.75 = chidist(17.75,7) =
0.013150336
Pachinko balls can be redeemed for prizes in the pachinko parlor. Then the player takes the prizes to a nearby building and sells them for cash.