HMD 436 Test #2 Name______________________
April 8, 2002
Consider a three reel single-line slot machine with weighted reels. The following table shows the total weights per reel for each symbol.
|
Symbol |
Reel 1 |
Reel 2 |
Reel 3 |
|
Bar |
3 |
2 |
1 |
|
Bell |
4 |
3 |
2 |
|
Plum |
5 |
4 |
3 |
|
Orange |
6 |
5 |
4 |
|
Blank |
14 |
18 |
22 |
|
Total |
32 |
32 |
32 |
1. 3 bars pays 1200, 3 bells pays 400, 3 plums pays 100, and 3 oranges pays 75, all per coin bet. Use the following table if you wish or Excel to determine the player’s expected return. (15 points total)
|
Payline |
Combinations |
Pays |
Return |
|
3 bars |
6 |
1200 |
7200 |
|
3 bells |
24 |
400 |
9600 |
|
3 plums |
60 |
100 |
6000 |
|
3 oranges |
120 |
75 |
9000 |
|
Total |
210 |
31800 |
Total return = ___31800______________
32^3=32768
Total combinations = __32768________________
31800/32768 = 0.9705
Expected return = __0.9705__________________
2. Consider a modified keno game in which there are 60 balls in the chamber, of which 15 will be drawn at random. The pick 6 game pays 1 for matching 3, 10 for matching 4, 100 for matching 5, and 1000 for matching 6. Use the following table if you wish or Excel for your work. (20 points total)
|
Match |
Combinations |
Pays |
Return |
|
3 |
6,860,137,775,400 |
1 |
6,860,137,775,400 |
|
4 |
1,435,842,790,200 |
10 |
14,358,427,902,000 |
|
5 |
143,584,279,020 |
100 |
14,358,427,902,000 |
|
6 |
5,317,936,260 |
1000 |
5,317,936,260,000 |
|
Total |
8,444,882,780,880 |
40,894,929,839,400 |
Total return = __
40,894,929,839,400_________________
Combin(60,15)=
53,194,089,192,720Total combinations = __
53,194,089,192,720__________________
40,894,929,839,400/53,194,089,192,720=0.768787105
Expected return = ___
0.768787105__________________
3. Consider a game of Derby with the following pay table. You may use the following table or Excel for your own work. (15 points total)
|
Quinella |
Pays |
Fair probability |
True probability |
Return |
|
1,2 |
95 |
0.010526316 |
0.009158708 |
0.870077 |
|
1,3 |
4 |
0.25 |
||
|
1,4 |
9 |
0.111111111 |
||
|
1,5 |
37 |
0.027027027 |
||
|
2,3 |
21 |
0.047619048 |
||
|
2,4 |
49 |
0.020408163 |
||
|
2,5 |
200 |
0.005 |
||
|
3,4 |
2 |
0.5 |
||
|
3,5 |
8 |
0.125 |
||
|
4,5 |
19 |
0.052631579 |
||
|
Total |
1.149323244 |
Fair probability of 1,2 quinella ____
0.010526316__________________
Sum of all ten fair probabilities ____
1.149323244___________________
0.010526316/1.149323244 = 0.009158708
Actual probability of 1,2 win _____
0.009158708__________________
95 *
0.009158708 = 0.870077, or…1/1.149323244 = 0.870077
Expected return of 1,2 win __
0.870077______________________
4. Consider the Royal Match side bet played with 5 decks. (20 points total)
How many combinations are there for a "royal match", in other words a suited king and queen?
4*5^2=4*25=100
How many combinations are there for a "easy match", in other words any suited pair besides a royal match?
4*((combin(13,2)-1)*5^2 + 13*combin(5,2)) = 4*(77*25 + 13*10) = 8220
How many combinations are there for two non-suited cards?
Combin(4,2)*(13*5)^2 = 6*4225 = 25350
Use the following table or Excel to determine the total return.
|
Hand |
Combinations |
Pays |
Value |
|
Royal match |
100 |
25 |
2500 |
|
Easy match |
8220 |
2.5 |
20550 |
|
Non-suited |
25350 |
-1 |
-25350 |
|
Total |
33670 |
-2300 |
Total value = _____-2300_______________
Total combinations = ____33670________________
-2300/33670=
Player’s expected value = ___-0.0683____________________
5. What is the probability of 2 suited sevens as the first two cards and then a non-seven in a 7-deck shoe of normal 52-card decks? (5 points)
(4*permut(7,2)*(48*7))/permut(52*7,3) = (4*42*336) / 47831784 = 0.001180
(permut(4,2)*permut(2,2)*(4*4)*(16*4-2))/permut(52*4,4) = (12*2*16*62)/1818254880 = 0.
(15-1)*(5^3-5) = 14*120 = 1680
How many combinations are there for a straight (not including a straight flush)?_____1680______________
5*(combin(15,3)-(15-1)) = 5*(455-14) = 2205
How many combinations are there for a flush (not including a straight flush)?____2205_______________
15*14*combin(5,2)*5 = 10500
How many combinations are there for a pair?___10500________________
(15*permut(5*8,2)*(14*permut(5*8,2)+permut(5*8-2,2)))/permut(15*5*8,4) =
0.004239Or….
Probability of first tie = 15*COMBIN(5*8,2)/COMBIN(75*8,2) = 0.065109
Probability of second tie = (14*COMBIN(5*8,2)+COMBIN(40-2,2))/COMBIN(75*8-2,2) = 0.065114
Probability of two consecutive ties = 0.065109 * 0.065114 = 0.004239