|
GAM 470 Test #2 April 5, 2005 |
Name_______Answers___________ |
Consider a keno game in which the casino draws 10 balls out of 40. A bet is available on a pick 6.
Combin(10,3)*combin(30,3) = 120*4060 = 487200
Combin(10,4)*combin(30,2) = 210*435 = 91,350
Combin(10,5)*30 = 252*30 = 7560
Combin(10,6) = 210
5. What is the total number of combinations for picking 6 numbers out of 40?
Combin(40,6) = 3838380
6. Following is the pay table. Fill in the rest of the table to find the total win over all combinations.
|
Catch |
Pays |
Probability Combinations |
Return Combinations |
|
0 |
0 |
||
|
1 |
0 |
||
|
2 |
0 |
||
|
3 |
3 |
487200 |
1461600 |
|
4 |
10 |
91350 |
913500 |
|
5 |
100 |
7560 |
756000 |
|
6 |
2000 |
210 |
420000 |
|
Total |
. |
3838380 |
3551100 |
What is the expected return?
3551100/3838380 = 92.52%.
7.
|
Bet |
Pays |
|
Arnold Schwarzenegger |
3 to 1 |
|
Jeb Bush |
5 to 1 |
|
John McCain |
7 to 1 |
|
Hillary Clinton |
2 to 1 |
|
John Edwards |
8 to 1 |
|
Rudy Guiliani |
4 to 1 |
|
Field |
15 to 1 |
|
Bet |
Pays |
Pays (for one) |
Inverse |
|
Arnold Schwarzenegger |
3 to 1 |
4 |
0.250000 |
|
Jeb Bush |
5 to 1 |
6 |
0.166667 |
|
John McCain |
7 to 1 |
8 |
0.125000 |
|
Hillary Clinton |
2 to 1 |
3 |
0.333333 |
|
John Edwards |
8 to 1 |
9 |
0.111111 |
|
Rudy Guiliani |
4 to 1 |
5 |
0.200000 |
|
Field |
15 to 1 |
16 |
0.062500 |
|
Total |
. |
. |
1.248611 |
As the above table shows the player must bet 1.248611 units to get back 1 unit. So the expected return is 1/1.248611 = 0.80089, or 80.09%.
|
Hand |
Expected |
Actual |
Measure of Deviation |
|
Royal flush |
1 |
2 |
1.0000 |
|
Straight flush |
9 |
7 |
0.4444 |
|
Four of a kind |
156 |
175 |
2.3141 |
|
Full house |
936 |
1000 |
4.3761 |
|
Flush |
1277 |
1250 |
0.5709 |
|
Straight |
2550 |
2450 |
3.9216 |
|
Three of a kind |
13728 |
13800 |
0.3776 |
|
Two pair |
30888 |
31000 |
0.4061 |
|
Jacks or better |
84480 |
85000 |
3.2008 |
|
All other |
515715 |
515056 |
0.8421 |
|
Total |
649740 |
649740 |
17.4536 |
What is the chi-squared statistic?_______17.4536_____________
For problems 11 to 16 consider a blackjack side bet based on the player’s first two cards and the dealer’s up card. There are five decks in the shoe.
4*combin(5,3) = 40
4*5^3 = 500
Combin(4*5,3) – 4*combin(5,3) = 1140 – 40 = 1100
(4*5)^3 - 4*5^3 = 8000 – 500 = 7500
4*combin(13*5,3) – 40 – 500 = 4*43680 – 540 = 174,180
|
Hand |
Pays |
Probability Combinations |
Return Combinations |
|
Suited 555 |
5000 to 1 |
40 |
200000 |
|
Suited 456 |
500 to 1 |
500 |
250000 |
|
Non-suited 555 |
200 to 1 |
1100 |
220000 |
|
Non-suited 456 |
100 to 1 |
7500 |
750000 |
|
Flush |
5 to 1 |
174180 |
870900 |
|
All other |
Loss |
2712300 |
-2712300 |
|
Total |
. |
2895620 |
-421400 |
Expected return = ________-14.55%________________
Probability of blackjack = (2*4)*(2*16)/combin(2*52,2) = 0.047796863.
Probability of losing = 1-0.047796863 = 0.952203
Expected value = 17*0.047796863 - 0.952203 = -0.13966.
So the house edge is +13.966%.
3 blue sock combinations = combin(7,3) = 35
2 green sock combinations = combin(5,2) = 10
Total successful combinations = 35*10 = 350.
Total all combinations = combin(15,5) = 3003.
Probability = 350/3003 = 11.66%.
Successful combinations = 9*6*6 = 324.
Total all combinations = combin(21,3) = 1330.
Probability = 324/1330 = 24.36%.
19 You remove all the face cards from a deck of cards. You then draw 5 cards from the remaining 40. What is the probability you get a two pair? (6 points)
Successful combinations =
combin(10,2)*8*combin(4,2)^2*4 = 45*8*6^2*4 = 51840Total all combinations = combin(40,5) = 658,008
Probability = 51840/658008 = 7.88%.